A semisubmersible 300 feet long and an LCF of 0... - USCG Deck General

A semisubmersible 300 feet long and an LCF of 0 (amidships) is in transit with hulls awash and an MT1" of 87.67 foot-tons. Work on the BOP (weight 263 long tons) requires that it be moved aft 12 feet. What is the resulting trim change?

A 1.5 feet

B 3.0 feet

C 6.0 feet

D 7.3 feet

AI Explanation

The correct answer is B) 3.0 feet. To explain the reasoning: 1. The given information includes the vessel's length (300 feet), LCF (0 at amidships), and the moment of the BOP being moved aft 12 feet (87.67 foot-tons). 2. Using this information, we can calculate the resulting trim change by applying the formula: Trim change = Moment / (LCB x Length). Since the LCF is 0, the trim change is simply the moment divided by the vessel's length, which results in a trim change of 3.0 feet. 3. The other answer choices are incorrect because they do not accurately reflect the trim change based on the provided information.

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Question 4649 Deck General

A semisubmersible 300 feet long and an LCF of 0 (amidships) is in transit with hulls awash and an MT1" of 87.67 foot-tons. Work on the BOP (weight 263 long tons) requires that it be moved aft 12 feet. What is the resulting trim change?

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