Question 486 Deck General

The correct answer is B) 3116. To arrive at this answer, we need to calculate the total volume of the cargo hold and then determine the maximum number of cases that can be stowed, accounting for the 15% broken stowage. The volume of the cargo hold is 44,000 bale cubic feet. Each case measures 4 ft by 2 ft by 1.5 ft, which gives a volume of 12 cubic feet per case. To find the maximum number of cases, we first calculate the total volume available for the cargo, which is 44,000 cubic feet. Accounting for the 15% broken stowage, the actual volume available for the cases is 44,000 x (1 - 0.15) = 37,400 cubic feet. Dividing the available volume by the volume of each case (37,400 / 12) gives us 3,116.67 cases. Rounding down to the nearest whole number, the maximum number of cases that can be stowed in the hold is 3,116. The other answer choices are incorrect because they do not accurately account for the 15% broken stowage factor.