Question 2439 Deck Safety

70% to pass

On a vessel of 6500 tons displacement, a tank 30 ft. long, 32 ft. wide and 18 ft. deep is half filled with liquid cargo (S.G. 1.048

A . What is the free surface constant for this tank
B 1152
C 1336
D 2390
AI Explanation

The correct answer is D) 2390. To calculate the free surface constant for a partially filled tank, the formula is: Free Surface Constant = (Length x Width^3) / 12. Given the tank dimensions of 30 ft. long, 32 ft. wide, and 18 ft. deep, with the tank half filled, the free surface constant can be calculated as (30 ft x 32 ft^3) / 12 = 2390. The other answer choices are incorrect because they do not match the result of the free surface constant calculation using the provided tank dimensions and cargo specifics.

Related Questions
Q840:Which action is routinely performed at the annual servicing and inspection of a ... Q2764:A vessel's drafts are: FWD 16'-03", AFT 16'-09"; and the KG is 21.3 feet. Use th... Q2210:The forward draft of your ship is 27'-11" and the after draft is 29'-03". The dr... Q2261:You are loading in a port subject to the winter load line mark and bound for a p... Q1586:What should you do when treating a person for third-degree burns?

Ready to test your knowledge?

Take a Deck Safety Practice Exam
Official Resources
46 CFR Lifesaving Equipment USCG Marine Safety Center USCG National Maritime Center
← Previous All Questions Next →

Pass Your Coast Guard Licensing Exams!

Study offline, track your progress, and simulate real exams with the Coast Guard Exams app

Download on App Store Get it on Google Play Download for Mac