Question 2464 Deck Safety

70% to pass

You are making a heavy lift with the jumbo boom. Your vessel displaces 8530 T. The 40-ton weight is on the pier and its center is 65' to starboard of the centerline. The head of the boom is 115' above the base line and the center of gravity of the lift when stowed on deck will be 50' above the base line. As the jumbo boom takes the strain the ship lists to 5°. What is the GM with the cargo stowed?

A 2.96 ft

B 3.18 ft

C 3.46 ft

D 3.77 ft

AI Explanation

The correct answer is D) 3.77 ft. This is determined by calculating the GM (Metacentric Height) of the vessel with the cargo stowed. The GM is a measure of a vessel's stability and indicates how much the vessel will heel or roll when subjected to an external force. To calculate the GM, we need to consider the vessel's displacement, the weight and position of the cargo, and the angle of list. Using the provided information, we can determine the GM to be 3.77 ft, which makes option D the correct answer. The other options are incorrect because they do not accurately represent the GM calculation based on the given data.

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