Question 2470 Deck Safety
70% to passIn order to check your vessel's stability, a weight of 40 tons is lifted with the jumbo boom, the boom head being 50 feet from the ship's centerline. The clinometer is then carefully read and shows a list of 5°. The vessel's displacement is 8,000 tons including the suspended weight. What will be the metacentric height of the vessel at this time?
A
2.74 feet
B
2.80 feet
C
2.86 feet
D
2.93 feet
AI Explanation
The correct answer is C) 2.86 feet. To calculate the metacentric height (GM) of the vessel, we can use the formula: GM = (Displacement x Distance of Weight)/[Weight x Tan(Angle of List)]. Plugging in the given values, we get: GM = (8,000 tons x 50 feet)/[40 tons x Tan(5°)] = 2.86 feet. The other answer choices are incorrect because they do not match the result of this calculation. This formula is a standard approach to determining the metacentric height based on the displacement, weight, and angle of list of the vessel.
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