Question 2668 Deck Safety

70% to pass

Your vessel displaces 564 tons. The existing deck cargo has a center of gravity of 1.5 feet above the deck and weighs 41 tons. If you load 22 tons of ground tackle with an estimated center of gravity of 2.5 feet above the deck, what is the final height of the CG of the deck cargo?

A 1.62 feet
B 1.85 feet
C 2.10 feet
D 2.46 feet
AI Explanation

The correct answer is B) 1.85 feet. To calculate the final height of the center of gravity (CG) of the deck cargo, we need to use the formula for calculating the weighted average of the CG. The formula is: (Existing CG x Existing Weight + New CG x New Weight) / (Existing Weight + New Weight) Given information: - Vessel displacement: 564 tons - Existing deck cargo CG: 1.5 feet above the deck - Existing deck cargo weight: 41 tons - New cargo (ground tackle) weight: 22 tons - New cargo CG: 2.5 feet above the deck Plugging the values into the formula: (1.5 x 41 + 2.5 x 22) / (41 + 22) = 1.85 feet The other options are incorrect because they do not correctly apply the formula for calculating the weighted average of the CG.

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Official Resources
46 CFR Lifesaving Equipment USCG Marine Safety Center USCG National Maritime Center
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