Question 2750 Deck Safety

70% to pass

A cargo of 40 tons is to be lifted with a boom located 40 feet from the ship's centerline. The ship's displacement including the suspended cargo is 8,000 tons and the GM is 2 feet with cargo suspended. What will the list of the vessel be with the cargo suspended?

A 4.9°
B 5.2°
C 5.7°
D 6.0°
AI Explanation

The correct answer is C) 5.7°. The reasoning is as follows: 1) The suspended cargo of 40 tons located 40 feet from the ship's centerline creates an overturning moment that will cause the ship to list. 2) Using the formula for calculating list (theta = [W * d] / [Displacement * GM]), the list angle is calculated to be 5.7°. 3) The other options are incorrect because they do not accurately reflect the calculation based on the given information. 4) The formula and calculation provide the justification for the 5.7° list angle being the correct answer.

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Official Resources
46 CFR Lifesaving Equipment USCG Marine Safety Center USCG National Maritime Center
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