Question 138Electricity & Electronics - QMED

The correct answer is C) immediately display a very low resistance value which remains low. When a digital multimeter is set to measure resistance (ohms) and connected to a shorted capacitor, the meter will display a very low resistance value. This is because a shorted capacitor effectively acts as a direct connection, allowing current to flow freely without any resistance. The other answer choices are incorrect because: A) the meter would not display a continuously dropping value, B) the meter would not remain at OL (overload), and D) the value would not continuously rise to OL, as a shorted capacitor would consistently display a very low resistance reading.