Question 79Electricity & Electronics - QMED
70% to passWhat will be the resulting current when a voltage of 442.7 VDC is applied to a resistance of 1.25 ohms in figure "A" of the illustrated circuit when the switch is closed? Illustration EL-0018
A28.25 amps
B35.32 amps
C354.16 amps
D443.62 amps
AI Explanation
The correct answer is C) 354.16 amps. This is calculated using Ohm's law, which states that the current (I) in a circuit is equal to the voltage (V) divided by the resistance (R). The formula is I = V/R. Plugging in the values given, we get I = 442.7 V / 1.25 ohms = 354.16 amps. The other answer choices are incorrect because they do not properly apply Ohm's law to the given circuit parameters. Choices A, B, and D do not accurately calculate the current when a 442.7 VDC voltage is applied across a 1.25 ohm resistance.
Related Questions
Q@q.QuestionNumber:If the voltage supplied to the lighting circuit is 110 volts, how much current i... Q@q.QuestionNumber:Which of the following characteristics is most critical in determining the wire ... Q@q.QuestionNumber:When an alternator is to remain idle for even a few days, what should be done? ... Q@q.QuestionNumber:In figure "2" of the diagram shown in the illustration, the three phase power tr... Q@q.QuestionNumber:With respect to motors, how is ambient temperature defined?
Ready to test your knowledge?
Take a Electricity & Electronics - QMED Practice ExamOfficial Resources
Want to practice with timed exams?
Download Coast Guard Exams for the full exam experience.
Get the App