Question 83Electricity & Electronics - QMED
70% to passWhat will be the resulting current when a voltage of 110 VDC is applied to a resistance of 32 ohms in figure "A" of the illustrated circuit when the switch is closed? Illustration EL-0018
A0.29 amps
B3.44 amps
C9.31 amps
D142 amps
AI Explanation
The correct answer is B) 3.44 amps. This is calculated using Ohm's law, which states that the current (I) is equal to the voltage (V) divided by the resistance (R). In this case, with a voltage of 110 VDC and a resistance of 32 ohms, the current is 110 V / 32 ohms = 3.44 amps. The other answer choices are incorrect because: A) 0.29 amps is too low and does not match the calculation. C) 9.31 amps is too high and does not match the calculation. D) 142 amps is significantly too high and does not match the calculation.
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