Question 824Navigation General

The correct answer is C) 059°. The beam width of the radar is 2°, which means the actual bearing of the small island is within 2° of the observed bearing of 056°pgc. Given the gyro error of 2°E, the true bearing of the island would be 056° + 2° = 058°. Therefore, the bearing that should be plotted on the chart is 059°. The other options are incorrect because: A) 052° is too low by 7°, since the true bearing is 058°. B) 056° is the observed bearing, not the corrected bearing. D) 060° is too high by 2°, since the true bearing is 058°.