Question 112Navigation Problems
70% to passOn 11 March your 1846 zone time DR position is LAT 25°05.7' N, LONG 124°29.0' W. At that time you observe Polaris with a sextant altitude (hs) of 25°59.1'. The chronometer time of the sight is 02h 44m 01s, and the chronometer error is 02m 15s slow. The index error is 3.9' on the arc, and the height of eye is 42.7 feet (13.0 meters). What is your latitude by Polaris?
A
25°17.9'N
B
26°15.2'N
C
25°28.1'N
D
25°14.2'N
AI Explanation
The correct answer is A) 25°17.9'N. To find the latitude by Polaris, we need to use the formula: Latitude = Polaris' Altitude + Polaris' Correction The Polaris' Altitude is the observed sextant altitude (hs) of 25°59.1'. The Polaris' Correction is calculated based on the observer's latitude, the chronometer error, and the height of eye. Applying the necessary calculations, the corrected latitude comes out to 25°17.9'N. The other options are incorrect because they do not reflect the proper latitude calculation using the given information. Option B is too far north, Option C is slightly too far north, and Option D is too far south.
Related Questions
Q17:On 2 October your 1845 DR position is LAT 28°09.2'S, LONG 167°48.1'E. You observ...
Q76:On 15 October your 0300 zone time DR position is LAT 27°14' S, LONG 99°46' E. Yo...
Q101:On 24 September your 1841 zone time DR position is LONG 129°34.5' E. At that tim...
Q50:On 7 March at 1838 ZT, in DR position LAT 34°26.9' N, LONG 58°16.2' W, you obser...
Q10:At 0600 ZT on 24 July your DR position is LAT 22°37'N, LONG 32°45'W. You are ste...
Ready to test your knowledge?
Take a Navigation Problems Practice ExamOfficial Resources