Question 23Navigation Problems
70% to passYou observe the lower limb of the Sun at a sextant altitude (hs) of 41°29.8' on 11 January. The index error is 2.4' off the arc. The height of eye is 68 feet. What is the observed altitude (Ho)?
A
41°39.4'
B
41°36.4'
C
41°42.0'
D
41°44.5'
AI Explanation
The correct answer is A) 41°39.4'. To calculate the observed altitude (Ho), we need to apply the following formula: Ho = hs + IE + (2.04 / √h) Where: - hs is the sextant altitude (41°29.8') - IE is the index error (2.4' off the arc) - h is the height of eye (68 feet) Plugging in the values, we get: Ho = 41°29.8' + 2.4' + (2.04 / √68) = 41°32.2' + 7.2' = 41°39.4' The other options are incorrect because they do not accurately apply the formula to calculate the observed altitude (Ho) based on the given information.
Related Questions
Q70:On 3 February your 0451 zone time DR position is LAT 24°15.0' S, LONG 124°24.0' ...
Q61:On 4 September your 1813 zone time DR position is LAT 24°18.0' S, LONG 95°16.0' ...
Q84:On 24 March your vessel is enroute from Cadiz to Norfolk. Evening twilight will ...
Q102:On 20 June your 1742 zone time DR position is LAT 24°55.0' S, LONG 8°19.6' E. Co...
Q54:On 25 April your 1130 DR position is LAT 24°50.0'N, LONG 61°25.0'W. Your vessel ...
Ready to test your knowledge?
Take a Navigation Problems Practice ExamOfficial Resources