On 27 March your 0730 zone time position is LAT... - USCG Navigation Problems

On 27 March your 0730 zone time position is LAT 28°16'N, LONG 56°37'W. Your vessel is on course 158°T at a speed of 15.0 knots. An observation of the Sun's lower limb is made at 0915 zone time. The chronometer reads 01h 14m 11s, and the chronometer error is 00m 53s slow. The observed altitude (Ho) is 45°10.7'. LAN occurs at 1150 zone time, and a meridian altitude of the Sun's lower limb is made. The observed altitude (Ho) is 65°32.8'. Determine the vessel's 1200 zone time position.

A LAT 27°11.6'N, LONG 56°04.2'W

B LAT 27°08.8'N, LONG 56°10.3'W

C LAT 27°08.8'N, LONG 56°04.2'W

D LAT 27°11.6'N, LONG 56°10.3'W

AI Explanation

The correct answer is C) LAT 27°08.8'N, LONG 56°04.2'W. This is determined by using the celestial navigation principles and formulas to solve for the vessel's 1200 zone time position based on the given information. The key steps are: 1. Calculate the vessel's position at 0915 zone time using the 0730 zone time position, course, and speed. 2. Use the 0915 zone time Sun observation to calculate the latitude. 3. Use the 1150 zone time meridian altitude observation to calculate the longitude. The other options are incorrect because they do not match the final calculated position.

Question 28Navigation Problems