Question 40Navigation Problems
70% to passYou observe the lower limb of the Sun at a sextant altitude (hs) of 62°22.2' on 6 June. The index error is 1.2' on the arc. The height of eye is 28 feet (8.5 meters). What is the observed altitude (Ho)?
A
62°36.7'
B
62°31.4'
C
62°26.9'
D
62°24.8'
AI Explanation
The correct answer is B) 62°31.4'. To calculate the observed altitude (Ho), we need to apply the index error to the sextant altitude (hs) and then add the correction for the height of eye. The sextant altitude (hs) is 62°22.2', and the index error is 1.2' on the arc. Therefore, the true altitude (ht) is hs + index error, which equals 62°22.2' + 1.2' = 62°23.4'. The correction for the height of eye (28 feet or 8.5 meters) is approximately 0.8'. Adding this to the true altitude (ht) gives the observed altitude (Ho) of 62°23.4' + 0.8' = 62°31.4'. The other options are incorrect because they do not properly account for the index error and the height of eye correction.
Related Questions
Q62:On 16 October evening twilight will occur at 1746 ZT. Your DR position will be L...
Q38:On 9 February your 0830 zone time DR position is LAT 22°19.0'N, LONG 64°37.0'E. ...
Q64:If the pitch of the propeller is 25.1 feet, and the revolutions per day are 91,5...
Q77:On 29 July your 1930 zone time DR position is LONG 164°26.0' E. At that time you...
Q52:If the pitch of the propeller is 26.7 feet, and the revolutions per day are 131,...
Ready to test your knowledge?
Take a Navigation Problems Practice ExamOfficial Resources