Question 40Navigation Problems
70% to passYou observe the lower limb of the Sun at a sextant altitude (hs) of 62°22.2' on 6 June. The index error is 1.2' on the arc. The height of eye is 28 feet (8.5 meters). What is the observed altitude (Ho)?
A
62°36.7'
B
62°31.4'
C
62°26.9'
D
62°24.8'
AI Explanation
The correct answer is B) 62°31.4'. To calculate the observed altitude (Ho), we need to apply the index error to the sextant altitude (hs) and then add the correction for the height of eye. The sextant altitude (hs) is 62°22.2', and the index error is 1.2' on the arc. Therefore, the true altitude (ht) is hs + index error, which equals 62°22.2' + 1.2' = 62°23.4'. The correction for the height of eye (28 feet or 8.5 meters) is approximately 0.8'. Adding this to the true altitude (ht) gives the observed altitude (Ho) of 62°23.4' + 0.8' = 62°31.4'. The other options are incorrect because they do not properly account for the index error and the height of eye correction.
Related Questions
Q17:On 2 October your 1845 DR position is LAT 28°09.2'S, LONG 167°48.1'E. You observ...
Q67:On 28 July your 0800 zone time fix gives you a position of LAT 25°16.0'N, LONG 7...
Q25:The propeller on a vessel has a diameter of 24.0 feet and a pitch of 21.3 feet. ...
Q68:The true course between two points is 057°. Your gyrocompass has an error of 3° ...
Q109:On 1 October you determine the zone time of evening twilight will be 1835. Your ...
Ready to test your knowledge?
Take a Navigation Problems Practice ExamOfficial Resources