Question 45Navigation Problems
70% to passOn 2 October your 1845 DR position was LAT 28°09.2'S, LONG 167°48.1'E. You observe a faint star through a hole in the clouds at a sextant altitude (hs) of 20°45.6' T, bearing 201.5°T. The index error is 1.3' off the arc, and the height of eye is 42 feet. The chronometer reads 07h 46m 19s and is 00m 51s fast. What star did you observe?
A
Alpha Muscae
B
Muhlifain
C
Beta Corvi
D
Cor Caroli
AI Explanation
The correct answer is A) Alpha Muscae. To determine the observed star, we need to calculate the celestial coordinates of the observed object and then compare it to the known positions of navigational stars. Given the provided information, we can calculate the observed object's altitude and azimuth. Using the celestial navigation formulas, the calculated altitude and azimuth match the characteristics of the star Alpha Muscae, which is the correct answer. The other options are incorrect because their celestial coordinates do not match the observed data.
Related Questions
Q116:On 15 March in DR position LAT 21°42.0'N, LONG 55°26.0'W, you take an ex-meridia...
Q55:On 17 November in DR position LAT 01°14.4'S, LONG 148°45.5'E, you take an ex-mer...
Q8:On 24 January your 0700 zone time DR position is LAT 22°25.0'N, LONG 46°10.0'W. ...
Q24:You are underway on course 106°T at a speed of 15.3 knots. You sight a buoy bear...
Q87:On 12 September your 0600 zone time (ZT) fix gives you a position of LAT 22°51.9...
Ready to test your knowledge?
Take a Navigation Problems Practice ExamOfficial Resources