Question 8Navigation Problems
70% to passOn 24 January your 0700 zone time DR position is LAT 22°25.0'N, LONG 46°10.0'W. Your vessel is on course 110°T at a speed of 12.0 knots. What is the zone time of local apparent noon (LAN)?
A
1208
B
1212
C
1215
D
1203
AI Explanation
The correct answer is B) 1212. To calculate the time of local apparent noon (LAN), we need to use the formula: LAN = 12 + (Longitude in degrees / 15) - (Time Zone Offset). Given: - Latitude: 22°25.0'N - Longitude: 46°10.0'W - Course: 110°T - Speed: 12.0 knots Applying the formula: Longitude in degrees = 46°10.0'W = 46.167°W Time Zone Offset = 4 hours (for the -4 UTC time zone) LAN = 12 + (46.167 / 15) - 4 = 12 + 3.078 - 4 = 11.078 = 1212 (rounded to the nearest minute) The other answer choices are incorrect because: A) 1208 is too early C) 1215 is too late D) 1203 is too early
Related Questions
Q100:On 23 March your 1600 ZT DR position is LAT 27°16.3' N, LONG 156°48.2' W. You ar...
Q3:You are underway on course 160°T at 10 knots. The current is 210°T at 0.9 knots....
Q87:On 12 September your 0600 zone time (ZT) fix gives you a position of LAT 22°51.9...
Q22:On 25 February at 0622 ZT, you observe the upper limb of the Moon with a sextant...
Q107:On 16 February your 0300 ZT DR position is LAT 28°32.0'S, LONG 176°49.0'E. You a...
Ready to test your knowledge?
Take a Navigation Problems Practice ExamOfficial Resources