Question 54
GLI05When the height of the metacenter is greater than the height of the center of gravity, the upright equilibrium position is stable and stability is _________.
AI Explanation
The Correct Answer is D.
### Explanation for D ("positive")
When the height of the metacenter ($\text{GM}$) is greater than the height of the center of gravity ($\text{G}$), the ship (or floating body) has a positive metacentric height ($\text{GM} = \text{KM} - \text{KG} > 0$, where $\text{K}$ is the keel and $\text{M}$ is the metacenter).
* A **positive metacentric height** signifies that the metacenter ($\text{M}$) is above the center of gravity ($\text{G}$).
* When a ship heels, a righting moment is generated, tending to return the ship to its upright position.
* This condition results in **stable equilibrium**, and this type of stability is universally termed **positive stability**.
Therefore, when the equilibrium position is stable, the stability itself is positive.
### Explanation of Why Other Options Are Incorrect
**A) neutral:**
Neutral stability occurs when the metacenter ($\text{M}$) coincides exactly with the center of gravity ($\text{G}$), resulting in a metacentric height ($\text{GM}$) of zero. In this state, if the body is tilted, it remains in the new tilted position without returning or capsizing. This contradicts the premise that the equilibrium position is stable (which implies a righting moment).
**B) unstable:**
Unstable equilibrium occurs when the metacenter ($\text{M}$) is below the center of gravity ($\text{G}$), resulting in a negative metacentric height ($\text{GM} < 0$). In this state, any small tilt generates a capsizing moment. This contradicts the premise that the upright equilibrium position is stable.
**C) negative:**
Negative stability is the technical term used to describe the condition of unstable equilibrium (where $\text{M}$ is below $\text{G}$). Since the prompt states the equilibrium is stable, the stability cannot be negative.
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