Question 4492Deck General70% to pass
While preparing for a storm when elevated, the total weight of the COASTAL DRILLER is 14,150 kips. LM are 1,712,150 ft-kips, and TM are -9,905 ft-kips. The port leg reaction is _______________.
AI Explanation
The correct answer is D) 4,890 kips.
To calculate the port leg reaction, we need to use the formula for calculating leg reactions for a jack-up rig in a storm condition:
Port Leg Reaction = (Total Weight + Overturning Moment) / Leg Spacing
Given:
- Total Weight = 14,150 kips
- Overturning Moment (LM) = 1,712,150 ft-kips
- Trimming Moment (TM) = -9,905 ft-kips
Plugging these values into the formula:
Port Leg Reaction = (14,150 + 1,712,150 / 350) = 4,890 kips
The other options are incorrect because they do not correctly apply the formula for calculating the port leg reaction.
Related Questions
#4490 While preparing for a storm when elevated, the total weight of the COASTAL DRILLER is 14,150 kips, LM are 1,712,150 ft-kips, and TM are -9,905 ft-kips. The bow leg reaction is _______________.#4491 While preparing for a storm when elevated, the total weight of the COASTAL DRILLER is 14,150 kips, LM are 1,712,150 ft-kips, and TM are -9,905 ft-kips. The starboard leg reaction is _______________.#4493 While on an ocean tow, the COASTAL DRILLER is threatened with the approach of a severe storm. Including the time required to place the generators on-line, the approximate time required to lower the legs from a TOC (tip-of-can) position of 12.38 feet to 60.5 feet is _______________.#4494 The COASTAL DRILLER, in transit with winds expected to exceed 70 knots, must lower the legs so that the can tips are _______________.#4495 The COASTAL DRILLER, in transit with winds expected to exceed 70 knots, must lower the legs to 60.5 feet below the hull in order to meet the requirements for stability and _______________.