Question 4620Deck General70% to pass
The DEEP DRILLER, at a draft of 60 feet, has a KGL of 55.4 feet and an LCG of 2.43 feet. What is the trim angle?
AI Explanation
The correct answer is D) 2° by the head.
To determine the trim angle, we can use the formula: Trim (in degrees) = arctan[(LCG)/(KGL)] * (180/π).
Given:
- Draft = 60 feet
- KGL = 55.4 feet
- LCG = 2.43 feet
Plugging these values into the formula:
Trim (in degrees) = arctan(2.43/55.4) * (180/π)
Trim (in degrees) = 2.5° by the head
Therefore, the trim angle is 2° by the head, which corresponds to answer choice D.
The other answer choices are incorrect because:
A) 2° by the stern is the opposite of the correct answer.
B) 4° by the head is too steep.
C) 4° by the stern is the opposite of the correct answer and too steep.
Related Questions
#4618 A semisubmersible in transit is at a draft of 19 feet. The depth of the lower hulls is 21 feet. How much bunker fuel at 54.0 lbs/cu ft could be taken on and still provide one foot of freeboard if the TPI is 52.3? #4619 While the DEEP DRILLER is loaded as shown in Sample Form #4 (Drilling), casing is accidentally dropped on the starboard side. Because the sounding level and starboard aft inclination are slowly increasing, you decide that tank 10S has minor damage. Among the possible corrective actions is _______________.#4621 The DEEP DRILLER, loaded as shown in Sample Load Form #2 (Ballast to Survival), suffers major damage which results in flooding in tank C3S. Pumping from tanks in the vicinity of the damage have proven ineffective. Your best countermeasure is to _______________.#4622 The DEEP DRILLER, at a draft of 60 feet, has 3,765 ft-tons of transverse moments. How much ballast should be transferred between tanks 1P and 1S to level the unit in list? #4623 The DEEP DRILLER departs a fresh water port at a draft of 19.5 feet. What will be the draft in sea water?