Question 4653Deck General70% to pass
What is the new location of the transverse center of gravity if 200 short tons are placed 10 feet to port of the centerline on a MODU with TCG 0.7 foot starboard of the centerline, and displacement 9,000 short tons?
AI Explanation
The correct answer is A) 0.47 foot starboard of centerline.
The reasoning is as follows:
1) The initial transverse center of gravity (TCG) is 0.7 foot starboard of the centerline.
2) When 200 short tons are placed 10 feet to port of the centerline, the new TCG will shift towards port, but the amount of shift depends on the vessel's displacement.
3) The formula to calculate the new TCG is: New TCG = (Initial TCG * Total Displacement - Load Moment) / Total Displacement
4) Plugging in the values, the new TCG is calculated to be 0.47 foot starboard of the centerline, which is the correct answer.
The other options are incorrect because they do not accurately reflect the new position of the transverse center of gravity based on the given information.
Related Questions
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