Question 4850Deck General70% to pass
The DEEP DRILLER, at 60.0 feet draft in sea water, has VM = 974,441 foot-long tons, LM = 40,301 foot-long tons, TM = 3 foot-long tons, FSML = 30,572 foot-long tons, and FSMT = 18,732 foot-long tons. What is the uncorrected height of the center of gravity?
AI Explanation
The correct answer is B) 53.78 feet.
To calculate the uncorrected height of the center of gravity, we can use the formula:
VCG = (VM * VM) / (LM + TM + FSML + FSMT)
Plugging in the given values:
VCG = (974,441 * 60.0) / (40,301 + 3 + 30,572 + 18,732)
= 58,466,460 / 89,608
= 53.78 feet
The other options are incorrect because they do not match the result of this calculation.
Related Questions
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