Question 4912Deck General70% to pass
A jack-up with a calculated moment to change list one inch (MCL1") of 1,200 foot- kips intends to transfer 100 kips of weight in a transverse direction. How far should the weight be transferred to change the draft on the port side from 11.5 to 11.0 feet?
AI Explanation
The correct answer is D) 144 feet.
The reason this is the correct answer is that the distance the weight should be transferred is directly proportional to the moment required to change the draft by 0.5 feet. Since the given moment to change list one inch (MCL1") is 1,200 foot-kips, and the weight to be transferred is 100 kips, the distance the weight should be transferred can be calculated using the formula: Distance = MCL1" / (100 kips).
Plugging in the values, we get: Distance = 1,200 foot-kips / (100 kips) = 12 feet. Since the question asks for the distance to change the draft by 0.5 feet, the correct answer is 12 feet x 12 = 144 feet.
The other options are incorrect because they do not accurately reflect the relationship between the given moment, weight, and distance required to change the draft by the specified amount.
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