Question 4985Deck General70% to pass
The COASTAL DRILLER, with no list, is at a true mean draft of 10 feet and 10 inches. LM is 1,699,463 ft-kips. Using only tanks 1, 25, and 26, how many kips of drill water must be transferred to level the jack-up?
AI Explanation
The correct answer is B) Transfer 53.1 kips each from 25 and 26 forward to 1.
To level the jack-up vessel, the goal is to transfer weight to reduce the list or trim. Since the vessel has no list, the issue is to reduce the trim. By transferring 53.1 kips of drill water from the aft tanks 25 and 26 to the forward tank 1, the trim will be reduced, bringing the vessel to an even keel.
The other options are incorrect because: A) transferring 106.2 kips aft would increase the trim; C) transferring 612 kips from 25 to 26 would not affect the trim; and D) the vessel is not level, so weight must be transferred to level it.
Related Questions
#4983 While in transit at a draft of 10.5 feet, the COASTAL DRILLER has a KGT of 60.0 feet. What is the GMT? #4984 What is the trim of a jack-up with a forward draft of 12 feet and an after draft of 13 feet? #4986 What is the change in the vertical moments (excluding free surface effects) for the COASTAL DRILLER if 2.0 feet of drill water is transferred from a full drill water tank 23 to an empty drill water tank 6? #4987 The COASTAL DRILLER has a change of trim by the head of 2.0 feet. What is the change of draft at the forward draft marks? #4988 What is the change in transverse moments for the Coastal Driller if 2.5 feet of drill water is discharged from drill water tank 23?