Question 5006Deck General70% to pass
A jack-up with a calculated moment to change list one inch (MCL1") of 1,350 foot- kips intends to transfer drill water from a tank with a TCG of 82 feet to a tank with a TCG of 18 feet. How much weight should be transferred to change the draft on the port side from 11.0 to 11.5 feet?
AI Explanation
The correct answer is D) 253.1 kips.
To determine the amount of weight that needs to be transferred, we can use the formula for calculating the moment to change list one inch (MCL1"):
MCL1" = Weight x Distance
Given:
- MCL1" = 1,350 foot-kips
- TCG of the tank being drained = 82 feet
- TCG of the tank being filled = 18 feet
- Desired change in draft on the port side = 0.5 feet (from 11.0 to 11.5 feet)
To find the weight that needs to be transferred, we can rearrange the formula:
Weight = MCL1" / (TCG of drained tank - TCG of filled tank)
Weight = 1,350 / (82 - 18)
Weight = 1,350 / 64
Weight = 253.1 kips
The other options are incorrect because they do not correctly apply the formula and calculate the necessary weight to be transferred.
Related Questions
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