Question 2269Deck Safety70% to pass
A bulk freighter 680 ft. in length, 60 ft. beam, with a waterplane coefficient of .84, is floating in salt water at a draft of 21'. How many long tons would it take to increase the mean draft by 1"?
AI Explanation
The correct answer is B) 81.6 tons.
To calculate the increase in draft, we can use the formula: Increase in draft = Change in displacement / (Waterplane area x Density of water).
Given the vessel's length (680 ft), beam (60 ft), and waterplane coefficient (0.84), we can calculate the waterplane area as 0.84 x 680 x 60 = 34,560 sq ft.
The density of saltwater is approximately 64 lb/cu ft. An increase in draft of 1 inch (1/12 ft) would result in an increase in displacement of 34,560 x 1/12 = 2,880 cu ft.
Converting this to long tons (1 long ton = 2,240 lb), we get 2,880 x 64 / 2,240 = 81.6 long tons.
Therefore, the correct answer is B) 81.6 tons.
Related Questions
#2267 In order to calculate the TPI of a vessel, for any given draft, it is necessary to divide the area of the waterplane by which of the following? #2268 A vessel's mean draft is 29'-07". At this draft, the TPI is 152. The mean draft after loading 1360 tons will be _______________.#2270 A vessel's drafts are: FWD 14'-04", AFT 15'-08". How much more cargo can be loaded to have the vessel down to the freeboard draft? (Use the information in Section 1, the blue pages, of the Stability Data Reference Book) #2271 A bulk freighter 580 ft. in length, 60 ft. beam, with a waterplane coefficient of .84 is floating in salt water at a draft of 21 ft. How many long tons would it take to increase the mean draft 1"? #2272 A vessel's drafts are: FWD 19'-00", AFT 17'-02". How much more cargo can be loaded to have the vessel down to the freeboard draft? (Use the information in Section 1, the blue pages, of the Stability Data Reference Book)