Question 2487Deck Safety70% to pass
A 7,000 ton displacement tankship carries two slack tanks of alcohol with a S.G. of 0.8. Each tank is 50 ft. long and 30 ft. wide. What is the reduction in GM due to free surface with the vessel floating in sea water, S.G. is 1.026?
AI Explanation
The correct answer is C) .72 ft.
The reduction in GM (Metacentric Height) due to free surface effect can be calculated using the formula: Reduction in GM = (I/V) * (1 - SG_liquid/SG_water), where I is the moment of inertia of the free surface, V is the volume of the vessel, and SG_liquid and SG_water are the specific gravities of the liquid and water, respectively.
In this case, with the given tank dimensions and specific gravity of the alcohol (0.8), the calculated reduction in GM is 0.72 ft. The other options are incorrect because they do not accurately reflect the reduction in GM based on the provided information.
Related Questions
#2485 On a vessel of 10,000 tons displacement, compute the reduction in metacentric height due to free surface in a hold having free water on the tank top. The hold is 40 feet long and 50 feet wide. What is the reduction in metacentric height? #2486 On a vessel of 12,000 tons displacement, a tank 60 feet long, 50 feet wide, and 20 feet deep is half filled with fresh water (SG 1.000 #2488 What is the reduction in metacentric height due to free surface when a tank 60 ft. wide and 60 ft. long is partially filled with saltwater? (The vessel's displacement is 10,000 tons.) #2489 A vessel carries three slack tanks of gasoline (SG .68 #2490 A shaft alley divides a vessel's cargo hold into two tanks, each 25 ft. wide by 50 ft. long. Each tank is filled with salt water below the level of the shaft alley. The vessel's displacement is 6,000 tons. What is the reduction in GM due to free surface effect?