Question 2500Deck Safety70% to pass
Your vessel displaces 740 tons and measures 141'L by 34'B. What is the reduction in GM due to free surface if the fish hold (41'L by 30'B by 9'D) is filled with 2.5 feet of water? (Each foot of water weighs 35.1 tons)
AI Explanation
The correct answer is D) 3.18 feet.
To calculate the reduction in GM (metacentric height) due to free surface, we need to use the formula: Reduction in GM = (IL / ∆), where I is the moment of inertia of the free surface, L is the length of the free surface, and ∆ is the vessel's displacement.
In this case, the fish hold is 41'L by 30'B by 9'D, and it is filled with 2.5 feet of water. The moment of inertia of the free surface is (41 x 30^3) / 12 = 27,270 ft^4. The weight of the water in the fish hold is 2.5 x 35.1 = 87.75 tons. Plugging these values into the formula, we get a reduction in GM of 3.18 feet.
The other answer choices are incorrect because they do not accurately reflect the reduction in GM based on the given information.
Related Questions
#2498 On a vessel of 8,000 tons displacement, compute the reduction in metacentric height due to free surface in a hold having free water in the tank tops. The hold is 40 feet long and 20 feet wide. What is the reduction in metacentric height? #2499 Your vessel displaces 696 tons and measures 135'L by 34'B. What is the reduction in GM due to free surface if the fish hold #2501 Your vessel displaces 750 tons and measures 151'L by 35'B. What is the reduction in GM due to free surface if the fish hold (60'L by 31'B by 10'D) is filled with 3.5 feet of water? (Each foot of water weighs 53.1 tons) #2502 Your vessel displaces 645 tons and measures 132'L by 34'B. What is the reduction in GM due to free surface if the fish hold #2503 Your vessel displaces 728 tons and measures 138'L by 31'B. What is the reduction in GM due to free surface if the fish hold