Question 2510Deck Safety70% to pass
The liquid mud tanks on your vessel measure 32'L by 15'B by 8'D. The vessel's displacement is 640 tons and the specific gravity of the mud is 1.8. What is the reduction in GM due to a pair of these tanks (p/s) being slack?
AI Explanation
The correct answer is C) 1.41 feet.
The reduction in GM (metacentric height) due to a pair of slack liquid mud tanks on the vessel can be calculated using the formula: Reduction in GM = (2 x LCG of tanks x Volume of tanks) / Displacement of vessel.
Given:
- Length of tanks = 32 feet
- Breadth of tanks = 15 feet
- Depth of tanks = 8 feet
- Specific gravity of mud = 1.8
- Displacement of vessel = 640 tons
Plugging in the values, we get:
Volume of each tank = 32 x 15 x 8 = 3,840 cubic feet
Volume of the pair of tanks = 2 x 3,840 = 7,680 cubic feet
Weight of the mud in the tanks = 7,680 x 1.8 = 13,824 tons
LCG of the tanks = 32/2 = 16 feet
Reduction in GM = (2 x 16 x 13,824) / 640 = 1.41 feet.
The other options are incorrect because they do not match the calculated value of 1.41 feet.
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