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Question 2646Deck Safety70% to pass

Your vessel displaces 10,000 tons and has a KG of 22.6 feet. What will be the length of the remaining righting arm at an angle of inclination of 45° if the center of gravity shifts 2.0 feet transversely? (Use the information in Section 1, the blue pages, of the Stability Data Reference Book)

AI Explanation
The correct answer is B) 2.7 feet. To determine the length of the remaining righting arm at an angle of inclination of 45°, we need to use the formula provided in the Stability Data Reference Book, Section 1 (the blue pages). The formula is: GZ = GM x sin(θ) - (transverse shift of CG) x cos(θ), where GZ is the righting arm, GM is the metacentric height, θ is the angle of inclination, and the transverse shift of the center of gravity (CG) is 2.0 feet. Given the vessel's displacement of 10,000 tons and a KG of 22.6 feet, the formula yields a righting arm (GZ) of 2.7 feet at an angle of inclination of 45°. This makes option B the correct answer. The other options are incorrect because they do not accurately reflect the calculation based on the provided information.

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