Question 2668Deck Safety70% to pass
Your vessel displaces 564 tons. The existing deck cargo has a center of gravity of 1.5 feet above the deck and weighs 41 tons. If you load 22 tons of ground tackle with an estimated center of gravity of 2.5 feet above the deck, what is the final height of the CG of the deck cargo?
AI Explanation
The correct answer is B) 1.85 feet.
To calculate the final height of the center of gravity (CG) of the deck cargo, we need to use the formula for calculating the weighted average of the CG. The formula is:
(Existing CG x Existing Weight + New CG x New Weight) / (Existing Weight + New Weight)
Given information:
- Vessel displacement: 564 tons
- Existing deck cargo CG: 1.5 feet above the deck
- Existing deck cargo weight: 41 tons
- New cargo (ground tackle) weight: 22 tons
- New cargo CG: 2.5 feet above the deck
Plugging the values into the formula:
(1.5 x 41 + 2.5 x 22) / (41 + 22) = 1.85 feet
The other options are incorrect because they do not correctly apply the formula for calculating the weighted average of the CG.
Related Questions
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