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Question 2672Deck Safety70% to pass

Your vessel displaces 497 tons. The existing deck cargo has a center of gravity of 2.5 feet above the deck and weighs 24 tons. If you load 18 tons of ground tackle with an estimated center of gravity of 18 inches above the deck, what is the final height of the CG of the deck cargo?

AI Explanation
The correct answer is B) 2.07 feet. To calculate the final height of the center of gravity (CG) of the deck cargo, we need to use the principle of moments. The total moment of the system must be equal to the sum of the individual moments. In this case, the total moment is the product of the total weight and the final CG height. The formula to calculate the final CG height is: (Existing CG weight x Existing CG height + New CG weight x New CG height) / (Existing CG weight + New CG weight). Plugging in the given values, we get: (24 tons x 2.5 feet + 18 tons x 1.5 feet) / (24 tons + 18 tons) = 2.07 feet. The other options are incorrect because they do not properly apply the principle of moments to calculate the final CG height.

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