The correct answer is A) it will probably burn out immediately. When many turns of an alternating current (AC) coil in a contactor become short-circuited, the coil will experience a significant increase in current flow, which can cause the coil to overheat and potentially burn out immediately. This is because the short-circuit effectively reduces the resistance of the coil, allowing more current to flow through it, leading to excessive heat generation and potential failure of the coil. The other options are incorrect because: B) it will not operate on reduced current, as the short-circuit will increase the current; C) it will not experience a temperature drop, as the increased current will cause the temperature to rise; and D) it will not have a higher resistance value, as the short-circuit will reduce the resistance of the coil.