Question 153General Subjects - Assistant Engineer70% to pass
Suppose a prime mover rotates at a steady speed of 900 rpm at rated full load and rotates at a steady speed of 1000 rpm at no load. Assuming that no adjustments have been made to the governor speed control setting, what is the speed regulation of the prime mover expressed in percent?
AI Explanation
The correct answer is B) 11.1%.
The speed regulation of a prime mover is calculated as the percentage difference between the no-load speed and the full-load speed, divided by the full-load speed. In this case, the no-load speed is 1000 rpm and the full-load speed is 900 rpm. The speed regulation can be calculated as (1000 - 900) / 900 * 100 = 11.1%.
The other options are incorrect because:
A) 10.0% is too low.
C) 88.9% is the reciprocal of the correct answer, which is incorrect.
D) 90.0% is too high.
Related Questions
#151 Which of the following statements is true concerning the application for an isochronous governor? #152 Which term represents how rapidly a speed control governor will complete a corrective action as the result of a load change? #154 Which of the following speed control devices is used strictly as a safety device to prevent prime mover damage and acts by shutting down the prime mover? #155 Which term represents the change in speed required before a speed control governor will initiate corrective action as the load changes? #156 If a hydraulic system is in continuous operation, and is equipped with an air cooled heat exchanger, the fan should _______________.