Question 9Motor Plants - Assistant Engineer70% to pass
A four cylinder, four-stroke cycle, single acting diesel engine has a 740 mm bore and a 1500 mm stroke. What indicated power will be developed if the average mean effective pressure is 18 kg/cm2 at a speed of 90 RPM?
AI Explanation
The correct answer is A) 3416 kW.
To calculate the indicated power of a four-cylinder, four-stroke diesel engine, we can use the formula:
Indicated Power (kW) = (P_me * L * A * N) / (60 * 1000)
Where:
P_me = Mean Effective Pressure (kg/cm^2)
L = Stroke (mm)
A = Bore Area (mm^2)
N = Engine Speed (RPM)
Plugging in the given values:
P_me = 18 kg/cm^2
L = 1500 mm
Bore = 740 mm
A = π * (740/2)^2 = 429,140 mm^2
N = 90 RPM
Calculating the indicated power:
Indicated Power = (18 * 1500 * 429,140 * 4 * 90) / (60 * 1000)
= 3416 kW
The other options are incorrect because they do not match the calculated value of 3416 kW based on the given engine parameters.
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