Question 824Navigation General70% to pass
The beam width of your radar is 2°. The left tangent bearing of a small island, as observed on the PPI scope, is 056°pgc. If the gyro error is 2°E, what bearing would you plot on the chart?
AI Explanation
The correct answer is C) 059°.
The beam width of the radar is 2°, which means the actual bearing of the small island is within 2° of the observed bearing of 056°pgc. Given the gyro error of 2°E, the true bearing of the island would be 056° + 2° = 058°. Therefore, the bearing that should be plotted on the chart is 059°.
The other options are incorrect because:
A) 052° is too low by 7°, since the true bearing is 058°.
B) 056° is the observed bearing, not the corrected bearing.
D) 060° is too high by 2°, since the true bearing is 058°.
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