Question 2Navigation Problems70% to pass
You observe the lower limb of the Sun at a sextant altitude (hs) of 34°51.4' on 18 October. The index error is 2.0' off the arc. The height of eye is 54 feet (16.5 meters). What is the observed altitude (Ho)?
AI Explanation
The correct answer is B) 35°01.2'.
To calculate the observed altitude (Ho), we need to apply the index error to the sextant altitude (hs). The index error is given as 2.0' off the arc, which means the sextant reading is 2.0' higher than the true altitude. Therefore, we need to subtract 2.0' from the sextant altitude (hs) of 34°51.4' to get the observed altitude (Ho), which is 35°01.2'.
The other options are incorrect because they do not properly account for the index error of 2.0' off the arc. Option A) 35°03.6' is too high, Option C) 35°05.2' is too high, and Option D) 35°07.4' is too high.
Related Questions
#1 On 2 February your 0400 zone time DR position is LAT 24°14.0' N, LONG 163°28.0' W. You are on course 322°T at a speed of 22 knots. Considering their magnitude, azimuth, and altitude, which group includes the three bodies best suited for a fix at star time?#3 You are underway on course 160°T at 10 knots. The current is 210°T at 0.9 knots. What is the course made good?#4 On 16 January your 0930 ZT DR position is LAT 26°07.0'S, LONG 51°43.0'E. Your vessel is on course 238°T at a speed of 17.0 knots. What is the ZT of local apparent noon (LAN)?#6 Your vessel is steering course 299°psc, variation for the area is 7°W, and deviation is 4°W. The wind is from the southwest, producing a 3° leeway. What true course are you making good?