Question 41Navigation Problems70% to pass
On 3 October your 0830 ZT position is LAT 26°15.0'S, LONG 73°16.0'E. Your vessel is on course 280°T at a speed of 19.0 knots. What is the ZT of local apparent noon (LAN)?
AI Explanation
The correct answer is B) 1201.
To determine the ZT of local apparent noon (LAN), we need to calculate the vessel's longitude at LAN and then convert it to ZT.
Given information:
- Position at 0830 ZT: LAT 26°15.0'S, LONG 73°16.0'E
- Course: 280°T
- Speed: 19.0 knots
The vessel's longitude at LAN can be calculated by multiplying the time difference between 0830 ZT and LAN (in hours) by the vessel's speed and adding the result to the initial longitude.
The time difference between 0830 ZT and LAN is approximately 2 hours and 31 minutes (2.517 hours), as LAN occurs at 1200 local time. Multiplying the time difference by the vessel's speed gives a longitude change of approximately 47.8 miles, which corresponds to a longitude of 72°28.2'E at LAN.
Converting this longitude to ZT gives a LAN time of 1201 ZT, which is the correct answer.
The other options are incorrect because they do not accurately calculate the vessel's longitude at LAN and the corresponding ZT.
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