Coast Guard Exams
Question 74Navigation Problems70% to pass

The propeller on a vessel has a diameter of 21.5 feet and a pitch of 24.5 feet. What would be the apparent slip if the vessel cruised 458 miles in a 23 hour day (observed distance) at an average RPM of 78?

AI Explanation
The correct answer is A) -5.6%. To calculate the apparent slip, we can use the formula: Apparent Slip = (Theoretical Speed - Actual Speed) / Theoretical Speed x 100 The theoretical speed is calculated using the propeller diameter, pitch, and RPM: Theoretical Speed = Propeller Diameter x Pitch x RPM / 33,000 Theoretical Speed = 21.5 ft x 24.5 ft x 78 RPM / 33,000 = 481.68 miles The actual speed is the observed distance of 458 miles in 23 hours, which is 19.91 miles per hour. Plugging these values into the formula: Apparent Slip = (481.68 miles - 19.91 miles) / 481.68 miles x 100 = -5.6% The other options are incorrect because: B) -12.3% is too high C) +12.3% is the wrong sign, as the slip is negative D) +5.6% is the wrong sign, as the slip is negative.

Related Questions

#72 On 12 April at 0515 ZT, morning stars were observed, and the vessel's position was determined to be LAT 21°05'S, LONG 16°30'W. Your vessel is steaming at 19 knots on a course of 278°T. A sextant observation of the Sun's lower limb is made at 0930 ZT. The chronometer reads 10h 28m 25s, and the sextant altitude (hs) is 40°15.9'. The index error is 2.5' off the arc, and the chronometer error is 2m 15s slow. Your height of eye on the bridge is 57 feet. What are the intercept (a) and azimuth (Zn) from the assumed position of this sight?#73 On 16 July your 1810 zone time DR position is LAT 24°16.5' S, LONG 162°52.0' E. Considering their magnitude, azimuth, and altitude, which group includes the three bodies best suited for a fix at star time?#75 On 26 November your 0535 DR position is LAT 27°18.9' S, LONG 30°18.4' E. You observe an unidentified planet bearing 085°T at an observed altitude (Ho) of 32°15.2'. The chronometer reads 03h 33m 16s, and is 01m 48s slow. What planet did you observe?#76 On 15 October your 0300 zone time DR position is LAT 27°14' S, LONG 99°46' E. You are on course 128°T at a speed of 19 knots. Considering their magnitude, azimuth, and altitude, which group includes the three bodies best suited for a fix at star time?#77 On 29 July your 1930 zone time DR position is LONG 164°26.0' E. At that time you observe Polaris with a sextant altitude (hs) of 23°46.8'. The chronometer time of the sight is 08h 32m 18s, and the chronometer error is 02m 26s fast. The index error is 2.7' on the arc, and the height of eye is 56.0 feet. What is your latitude by Polaris?

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