Question 89Navigation Problems70% to pass
On 10 October your 0930 zone time position is LAT 25°00.0'S, LONG 164°38.6'W. Your vessel is on course 180°T at a speed to 10.0 knots. What is the zone time of local apparent noon (LAN)?
AI Explanation
The correct answer is A) 1145.
To determine the time of local apparent noon (LAN), we need to calculate the longitude difference between the vessel's position and the standard meridian of the time zone, and then use that to calculate the time difference from zone time to local apparent time.
Given:
- Vessel position: LAT 25°00.0'S, LONG 164°38.6'W
- Course: 180°T
- Speed: 10.0 knots
The longitude difference between the vessel's position and the standard meridian of the time zone (which is 180°W for the zone time given) is 164°38.6'W. This corresponds to a time difference of 10 hours and 58 minutes, which, when subtracted from the zone time of 0930, results in a local apparent noon time of 1145.
The other options are incorrect because they do not accurately account for the longitude difference and the resulting time difference from zone time to local apparent time.
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