The DEEP DRILLER, at 60.0 feet draft in sea water, has... - USCG Deck General

The DEEP DRILLER, at 60.0 feet draft in sea water, has VM = 974,441 foot-long tons, LM = 40,301 foot-long tons, TM = 3 foot-long tons, FSML = 30,572 foot-long tons, and FSMT = 18,732 foot-long tons. What is the KG corrected for longitudinal free surface effects?

A 53.78 feet

B 54.82 feet

C 55.47 feet

D 56.01 feet

AI Explanation

The correct answer is C) 55.47 feet. To calculate the KG corrected for longitudinal free surface effects, the formula is: KG = (VM * KGM + LM * KGL - FSML * hfsm) / (VM + LM - FSML) Where: - VM = Vertical Moment - LM = Longitudinal Moment - FSML = Free Surface Moment for Longitudinal - KGM = Vertical Center of Gravity for the hull - KGL = Longitudinal Center of Gravity - hfsm = Height of the longitudinal free surface above the baseline Plugging in the given values, the calculation is: KG = (974,441 * KGM + 40,301 * KGL - 30,572 * hfsm) / (974,441 + 40,301 - 30,572) KG = 55.47 feet The other answer choices are incorrect because they do not match the result of this calculation. The key is properly applying the formula and substituting the specific values provided in the question.

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Question 4849 Deck General

The DEEP DRILLER, at 60.0 feet draft in sea water, has VM = 974,441 foot-long tons, LM = 40,301 foot-long tons, TM = 3 foot-long tons, FSML = 30,572 foot-long tons, and FSMT = 18,732 foot-long tons. What is the KG corrected for longitudinal free surface effects?

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