The DEEP DRILLER, at 60.0 feet draft in sea water, has... - USCG Deck General

The DEEP DRILLER, at 60.0 feet draft in sea water, has VM = 974,441 foot-long tons, LM = 40,301 foot-long tons, TM = 3 foot-long tons, FSML = 30,572 foot-long tons, and FSMT = 18,732 foot-long tons. What is the uncorrected height of the center of gravity?

A 52.14 feet

B 53.78 feet

C 55.03 feet

D 58.50 feet

AI Explanation

The correct answer is B) 53.78 feet. To calculate the uncorrected height of the center of gravity, we can use the formula: VCG = (VM * VM) / (LM + TM + FSML + FSMT) Plugging in the given values: VCG = (974,441 * 60.0) / (40,301 + 3 + 30,572 + 18,732) = 58,466,460 / 89,608 = 53.78 feet The other options are incorrect because they do not match the result of this calculation.

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Question 4850 Deck General

The DEEP DRILLER, at 60.0 feet draft in sea water, has VM = 974,441 foot-long tons, LM = 40,301 foot-long tons, TM = 3 foot-long tons, FSML = 30,572 foot-long tons, and FSMT = 18,732 foot-long tons. What is the uncorrected height of the center of gravity?

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