Question 65Navigation Problems
70% to passIf the speed necessary for reaching port at a designated time is 23.7 knots and the pitch of the propeller is 20.8 feet, how many revolutions per minute will the shaft have to turn, assuming a 7% negative slip?
A
124
B
108
C
112
D
116
AI Explanation
The correct answer is B) 108 revolutions per minute. To calculate the required shaft revolutions per minute, we can use the formula: Shaft RPM = Speed / (Pitch * (1 - Slip)) Given information: - Speed = 23.7 knots - Pitch = 20.8 feet - Slip = 7% Plugging in the values: Shaft RPM = 23.7 / (20.8 * (1 - 0.07)) Shaft RPM = 23.7 / (20.8 * 0.93) Shaft RPM = 108 The other options are incorrect because they do not correctly apply the formula and account for the 7% negative slip.
Related Questions
Q97:On 14 January your 0550 DR position is LAT 25°26.0'N, LONG 38°16.0'W. You observ...
Q50:On 7 March at 1838 ZT, in DR position LAT 34°26.9' N, LONG 58°16.2' W, you obser...
Q10:At 0600 ZT on 24 July your DR position is LAT 22°37'N, LONG 32°45'W. You are ste...
Q45:On 2 October your 1845 DR position was LAT 28°09.2'S, LONG 167°48.1'E. You obser...
Q93:On 4 January your 0800 zone time DR position is LAT 25°25.0 S, LONG 16°09.0'W. Y...
Ready to test your knowledge?
Take a Navigation Problems Practice ExamOfficial Resources