Question 4400Deck General70% to pass
The DEEP DRILLER is drilling at 60 feet draft at a corrected KG of 54.0 feet. Ballast added or discharged to remain at a constant draft is at a VCG of 10 feet. How much non-liquid load would have to be removed from an average height of 130 feet above the keel to meet the maximum allowable KG at a draft of 60 feet for winds greater than 70 knots?
AI Explanation
The correct answer is D) 302 long tons.
The reasoning is as follows:
1. The DEEP DRILLER has a draft of 60 feet and a corrected KG (vertical center of gravity) of 54.0 feet.
2. To meet the maximum allowable KG at a draft of 60 feet for winds greater than 70 knots, the non-liquid load would need to be removed from an average height of 130 feet above the keel.
3. The amount of non-liquid load that needs to be removed is 302 long tons, as this would reduce the KG to the maximum allowable level.
4. The other options are incorrect because they do not accurately reflect the necessary reduction in non-liquid load to meet the maximum allowable KG for the given conditions.
Related Questions
#4398 Adding the transverse free surface correction to the uncorrected height of the center of gravity of a MODU yields _______________.#4399 The DEEP DRILLER as currently configured is limited to a maximum drilling depth of _______________.#4401 The DEEP DRILLER is planning to operate while loaded as shown in the Sample Load Form #3 ( Preparing to Drill). What is the margin between KGT and maximum allowable KG? #4402 When the height of the metacenter has the same value as the height of the center of gravity, the metacentric height is equal to _______________.#4403 The DEEP DRILLER is loaded as shown in the Sample Load Form #1 (Transit). What is the new height of the center of gravity corrected for longitudinal free surface effects if the entire contents of Salt Water Ballast Tanks 1P and 1S are discharged?