Question 4815Deck General70% to pass
What is the longitudinal shift in the center of gravity if 200 short tons is moved ten feet to port and 30 feet forward on a MODU with a displacement of 8,960 long tons?
AI Explanation
The correct answer is C) 0.67 foot.
To calculate the longitudinal shift in the center of gravity, we can use the formula: Longitudinal shift = (Mass x Longitudinal distance) / Displacement.
In this case, the mass moved is 200 short tons (or 180 long tons), the longitudinal distance is 30 feet, and the displacement of the MODU is 8,960 long tons. Plugging these values into the formula, we get a longitudinal shift of 0.67 foot.
The other options are incorrect because they do not accurately reflect the calculation based on the given information.
Related Questions
#4813 A semisubmersible displacing 18,000 long tons has an LCG 2 feet forward of amidships. Bulk, weighing 400 long tons, is discharged from P-tanks located 50.8 feet aft of amidships. What is the new LCG? #4814 A semisubmersible, with a TCG of 0.5 feet to port, displaces 20,000 long tons. Bulk, weighing 400 long tons, is discharged from P-tanks located 50 feet starboard of the centerline. What is the new TCG? #4816 A semisubmersible displacing 17,600 long tons has an LCG 3.2 feet forward of amidships. Bulk, weighing 400 long tons, is loaded into P-tanks located 50.8 feet aft of amidships. What is the new LCG? #4817 What is the transverse shift in the center of gravity if 200 short tons are placed 10 feet to port of the centerline on a MODU with TCG 0.7 foot starboard of the centerline, and the displacement is 9,000 short tons? #4818 A semisubmersible, while floating level, displaces 20,000 long tons. LCB is 3.0 feet forward of amidships. Bulk, weighing 300 long tons, is placed in P-tanks located 40 feet aft of amidships. What is the new LCG?