Question 4816Deck General70% to pass
A semisubmersible displacing 17,600 long tons has an LCG 3.2 feet forward of amidships. Bulk, weighing 400 long tons, is loaded into P-tanks located 50.8 feet aft of amidships. What is the new LCG?
AI Explanation
The correct answer is C) 2.00 feet forward of amidships.
To calculate the new LCG, we need to use the formula for the center of gravity:
New LCG = (Original LCG * Original Displacement + Load Moment) / New Displacement
Given:
Original LCG = 3.2 feet forward of amidships
Original Displacement = 17,600 long tons
Load Moment = 400 long tons * 50.8 feet aft = 20,320 long ton-feet
New Displacement = 17,600 + 400 = 18,000 long tons
Plugging these values into the formula:
New LCG = (3.2 * 17,600 + 20,320) / 18,000
New LCG = 2.00 feet forward of amidships
The other options are incorrect because they do not correctly apply the formula to calculate the new LCG based on the given information.
Related Questions
#4814 A semisubmersible, with a TCG of 0.5 feet to port, displaces 20,000 long tons. Bulk, weighing 400 long tons, is discharged from P-tanks located 50 feet starboard of the centerline. What is the new TCG? #4815 What is the longitudinal shift in the center of gravity if 200 short tons is moved ten feet to port and 30 feet forward on a MODU with a displacement of 8,960 long tons? #4817 What is the transverse shift in the center of gravity if 200 short tons are placed 10 feet to port of the centerline on a MODU with TCG 0.7 foot starboard of the centerline, and the displacement is 9,000 short tons? #4818 A semisubmersible, while floating level, displaces 20,000 long tons. LCB is 3.0 feet forward of amidships. Bulk, weighing 300 long tons, is placed in P-tanks located 40 feet aft of amidships. What is the new LCG? #4819 A semisubmersible, while floating level, displaces 18,000 long tons. Bulk, weighing 400 long tons, is placed in P-tanks located 80 feet to starboard of the centerline. What is the new TCG?