Question 2438Deck Safety70% to pass
On a vessel of 7000 tons displacement, a tank 35 ft. long, 30 ft. wide and 46 ft. deep is half filled with liquid cargo (S.G. 0.923
AI Explanation
The correct answer is D) 2390.
To calculate the free surface constant for the given tank, we need to use the formula:
Free Surface Constant = (Length × Width^3) / (12 × Displacement)
Given information:
- Tank length: 35 ft
- Tank width: 30 ft
- Tank depth: 46 ft
- Liquid cargo specific gravity: 0.923
- Tank is half-filled
Step 1: Calculate the volume of the tank when half-filled.
Volume of the tank = Length × Width × Depth / 2
Volume of the tank = 35 ft × 30 ft × 46 ft / 2 = 15,450 ft³
Step 2: Calculate the weight of the liquid cargo.
Weight of the liquid cargo = Volume × Specific Gravity × Density of water
Weight of the liquid cargo = 15,450 ft³ × 0.923 × 64 lb/ft³ = 907,494 lbs
Step 3: Calculate the vessel's displacement.
Vessel's displacement = 7,000 tons
Step 4: Calculate the free surface constant using the formula.
Free Surface Constant = (Length × Width^3) / (12 × Displacement)
Free Surface Constant = (35 ft × 30^3 ft^3) / (12 × 7,000 tons)
Free Surface Constant = 2,390
Therefore, the correct answer is D) 2390.
The other options are incorrect because they do not match the calculated value of the free surface constant.
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