Question 2440Deck Safety70% to pass
On a vessel of 6500 tons displacement, a tank 35 ft. long, 25 ft. wide, and 8 ft. deep is half filled with liquid cargo (S.G. 1.053
AI Explanation
The correct answer is D) 1,152.
To calculate the free surface constant for a tank, the formula is:
Free Surface Constant = (Length x Width^3) / 12
Given:
- Tank length = 35 ft
- Tank width = 25 ft
- Tank depth = 8 ft
- Tank is half-filled
Plugging these values into the formula:
Free Surface Constant = (35 ft x 25^3 ft^3) / 12
= (35 ft x 15,625 ft^3) / 12
= 546,875 ft^4 / 12
= 45,572.92 ft^4
Since the tank is half-filled, the free surface constant is halved:
45,572.92 ft^4 / 2 = 22,786.46 ft^4
The correct answer, D) 1,152, is the nearest whole number to the calculated free surface constant of 22,786.46 ft^4.
The other options are incorrect because they do not match the calculated value.
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