Question 2468Deck Safety70% to pass
To check stability, a weight of 40 tons is lifted with the jumbo boom, whose head is 40 feet from the ship's centerline. The clinometer shows a list of 6.5° with the weight suspended. Displacement including weight is 16,000 tons. What would be the GM while in this condition?
AI Explanation
The correct answer is C) 0.88 foot.
To calculate the GM (Metacentric Height) in this scenario, we can use the formula:
GM = (Displacement * Tangent of Angle of List) / (Weight Lifted)
Given:
- Displacement (including weight) = 16,000 tons
- Angle of List = 6.5°
- Weight Lifted = 40 tons
- Distance of Boom Head from Centerline = 40 feet
Plugging in the values, we get:
GM = (16,000 * Tan 6.5°) / 40
GM = (16,000 * 0.1138) / 40
GM = 0.88 foot
The other answer choices are incorrect because they do not accurately reflect the GM calculation based on the given information.
Related Questions
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