Question 2470Deck Safety70% to pass
In order to check your vessel's stability, a weight of 40 tons is lifted with the jumbo boom, the boom head being 50 feet from the ship's centerline. The clinometer is then carefully read and shows a list of 5°. The vessel's displacement is 8,000 tons including the suspended weight. What will be the metacentric height of the vessel at this time?
AI Explanation
The correct answer is C) 2.86 feet.
To calculate the metacentric height (GM) of the vessel, we can use the formula: GM = (Displacement x Distance of Weight)/[Weight x Tan(Angle of List)].
Plugging in the given values, we get: GM = (8,000 tons x 50 feet)/[40 tons x Tan(5°)] = 2.86 feet.
The other answer choices are incorrect because they do not match the result of this calculation. This formula is a standard approach to determining the metacentric height based on the displacement, weight, and angle of list of the vessel.
Related Questions
#2468 To check stability, a weight of 40 tons is lifted with the jumbo boom, whose head is 40 feet from the ship's centerline. The clinometer shows a list of 6.5° with the weight suspended. Displacement including weight is 16,000 tons. What would be the GM while in this condition? #2469 To check stability, a weight of 10 tons is lifted with the jumbo boom whose head is 45 ft. from the ship's centerline. The clinometer show's a list of 5.0° with weight suspended. Displacement including the weight is 9,000 tons. What would be the GM in this condition? #2471 What is the reduction in metacentric height due to free surface when a tank 60 feet long and 30 feet wide is partially filled with salt water, and is fitted with a centerline bulkhead? (The vessel has a displacement of 10,000 tons.) #2472 On a vessel of 9,000 tons displacement, compute the reduction in metacentric height due to free surface in a hold having free water on the tank tops. The hold is 20 feet long and 30 feet wide. What is the reduction in metacentric height? #2473 On a vessel of 12,500 tons displacement, compute the reduction in metacentric height due to free surface in a hold having free water on the tank top. The hold is 35 feet long and 50 feet wide. What is the reduction in metacentric height?